Turbocharged Purple Pearl ??!!

[TheJesus]

Been busy for sometime. Back with a hot one ! Why can one Purple Pearl hook much more than the other? See here ------>



Comments/feedback welcome !

[TomaHawk]

One factor I have never heard anyone talk about is torque. Torque would be the amount of force that is applied to the bowling ball at the point of release. I guess, it is not measurable?

The heavier the ball, the greater the resistance. But, it is not just a weight factor. Rolling a heavier ball requires more strength throughout the approach.

Torque, the precise moment the ball is about to leave the fingers. Let's call it: The Spring Board Effect.

Illustration, imagine two people, one light, one heavy jumping off a diving board. Obviously, the heavier person is going to be applying more downward force on the board when compared to a lighter person. The extra downward force is going to create a greater reactionary response in the diving board.

That is the same sort of sensation a bowler feels when releasing a 16# ball, especially when compared to a 14# ball.

It's not really apples and apples.

On another point, to all of you who are at odds with going to a lighter ball. What happens to a diving board when the person is too heavy??? Go to a lighter ball, your body and mind will thank you for it.

[Glenn]

Alrighty, T-Hawk, you drew me out. LOL!
I hope you posting doesn't "kill" this thread.

Yeah, torque refers to the smoothness or flippiness of the ball from the breakpoint to the pins.
A high-torque ball will flip the most, obviously; and, a low-torque ball will have the most even break.
Torque ratings are usually on a scale of 1-10.

Bowlers who generate more torque through their release may prefer a bowling ball with less torque... just sayin'.
Torque doesn't measure the amount of hook, only the shape of it.

In the case of the 15# Hammer Purple Solid, the torque is reported to be 6.2; and, just for fun, the 15# Hammer Ocean Vibe is given as 6.7

But, I'm no expert so your mileage may vary.....

[TomaHawk]

Agreed, when a bowling ball comes in contact with friction, that torque created by the core of a bowling ball is a factor. (We all know the coverstock has a lot of influence). In the video, given that the coverstocks are relatively the same, the difference between the lighter ball and the heavier ball is significant.

I once experimented with lighter weight bowling balls. The two most interesting things that were noticeable, where the ball felt weightless in the swing and the way the ball came off my hand.

The lighter ball felt less resistant to swing acceleration. The lack of resistance caused my hand to snap early, more violently, and had to be mechanically / fundamentally slowed. The acceleration point had to be physically delayed. Loss of torque.

With the heavier ball, gravity provides all of the necessary resistance needed to effectively swing / release the bal. The heavier ball allowed my body, arm, wrist, and fingers to load up on the ball without fear of the hand accelerating too fast. All of that increases torque off the hand. Torque isn't always useful, it has to be applied accordingly.

That's why bowling is an art form*.

[Glenn]

T-Hawk, now you're just showing off.

Yeah, you can't use "core torque" by itself, you can use it to adjust the back-end.
As you say, other things factor in: release, ball surface, conditions, coverstock, cores with flip blocks, asym, core density, drilling, etc., etc.

No, I'm sure this is all science...LOL!

[TomaHawk]

I wonder, has “the weight of the ball” issue ever been established through the use of a robo bowler?

[Glenn]

T-Hawk, you're just trying to get a fuss started.

We don't need a ThroBot to address this issue; just some good ole laws of physics and math.
And, maybe Ron Hatfield's book "Bowling Beyond the Basics". LOL!
Ron stated in his book that a 14# bowling ball will hit harder than a 15# bowling ball.

So, let's introduce the formula for the kinetic energy of an object in motion: KE = 1/2*m*v** in joules.
KE = 1/2 (14lbs x 16mph ^2) = 179.2J
KE = 1/2 (15lbs x 16mph ^2) = 192.0J
KE = 1/2 (16lbs x 16mph ^2) = 204.8J
Well, alrighty, that proves the 16# bowling ball hits harder. Ummm, maybe...

That bowling ball isn't going to roll itself.
Let's introduce MOMENTUM (p = mv) into the equation which is the quantity of motion of a moving bowling ball.

We assume we have a burly guy like T-Hawk who can deliver the ball at 48.5 km/sec (arbitrary amount of momentum for this example).
The result of different bowling ball weights being launched at the same momentum results in a difference of speed.
(There's that speed thing that T-Hawk is always babbling about...LOL)

Now, looking at the equations:
KE = 1/2 (14lbs x 17.1mph ^2) = 204.7J
KE = 1/2 (15lbs x 16.0mph ^2) = 192.0J
KE = 1/2 (16lbs x 14.9mph ^2) = 178.8J
The results indicate that the 14# bowling ball will hit harder. QED.

As always, I'm no expert, and don't claim to be one...your mileage may vary.

[TheJesus]

One factor I have never heard anyone talk about is torque. Torque would be the amount of force that is applied to the bowling ball at the point of release. I guess, it is not measurable?

The heavier the ball, the greater the resistance. But, it is not just a weight factor. Rolling a heavier ball requires more strength throughout the approach.

Torque, the precise moment the ball is about to leave the fingers. Let's call it: The Spring Board Effect.

Illustration, imagine two people, one light, one heavy jumping off a diving board. Obviously, the heavier person is going to be applying more downward force on the board when compared to a lighter person. The extra downward force is going to create a greater reactionary response in the diving board.

That is the same sort of sensation a bowler feels when releasing a 16# ball, especially when compared to a 14# ball.

It's not really apples and apples.

On another point, to all of you who are at odds with going to a lighter ball. What happens to a diving board when the person is too heavy??? Go to a lighter ball, your body and mind will thank you for it.

Not easy to measure that force, but in modern bowling we do not want to lift the ball, we want to rotate the hand around it.
Now my release is by no means modern. But i try to not push or lift the ball at least, as much as i can. So the force applied to both balls is probably the same. This is why i get less ROM with the 16p one.

Not so sure about the analogy with the diving board doesn't sound to apply to bowling because you have another material there (the board) that can accumulate elastic tension and gives it back the same way. In bowling we try to create speed only by the tempo of the feet and the height of the swing. I do not push/muscle the ball on the swing. If i do so, the 16 ball can hurt my elbow. The extra weight actually helped me relax more and more. The hard way, but at least i noticed it quickly and didn't get permanent damage. Only my 3 urethane type balls are 16. The rest of my arsenal is 15 btw. So i notice every little difference between these weights. This 14p Purple was the Pro Shop Operator's.

Thanks for the feedback and for watching !

[TheJesus]

T-Hawk, you're just trying to get a fuss started.

We don't need a ThroBot to address this issue; just some good ole laws of physics and math.
And, maybe Ron Hatfield's book "Bowling Beyond the Basics". LOL!
Ron stated in his book that a 14# bowling ball will hit harder than a 15# bowling ball.

So, let's introduce the formula for the kinetic energy of an object in motion: KE = 1/2*m*v** in joules.
KE = 1/2 (14lbs x 16mph ^2) = 179.2J
KE = 1/2 (15lbs x 16mph ^2) = 192.0J
KE = 1/2 (16lbs x 16mph ^2) = 204.8J
Well, alrighty, that proves the 16# bowling ball hits harder. Ummm, maybe...

That bowling ball isn't going to roll itself.
Let's introduce MOMENTUM (p = mv) into the equation which is the quantity of motion of a moving bowling ball.

We assume we have a burly guy like T-Hawk who can deliver the ball at 48.5 km/sec (arbitrary amount of momentum for this example).
The result of different bowling ball weights being launched at the same momentum results in a difference of speed.
(There's that speed thing that T-Hawk is always babbling about...LOL)

Now, looking at the equations:
KE = 1/2 (14lbs x 17.1mph ^2) = 204.7J
KE = 1/2 (15lbs x 16.0mph ^2) = 192.0J
KE = 1/2 (16lbs x 14.9mph ^2) = 178.8J
The results indicate that the 14# bowling ball will hit harder. QED.

As always, I'm no expert, and don't claim to be one...your mileage may vary.

I have read that book and talked to the physicist who helped write it. Their math is correct, BUT....they assume that you will throw the heavier ball slower (same momentum). If you throw both at same speed (perfectly do-able) the heavier one will have greater momentum, more energy to the pins.

[TomaHawk]

Not so sure about the analogy with the diving board